What is the solution to the equation: 4y + 12 = 28?

What is the solution to the equation: 4y + 12 = 28?

• A. 2
• B. 3
• C. 4
• D. 5

Answer: (C)

To find the solution to the equation 4y + 12 = 28, you need to isolate the variable y. First, start by subtracting 12 from both sides of the equation to eliminate the constant term on the left side: 4y + 12 - 12 = 28 - 12 This simplifies to: 4y = 16 Next, to solve for y, divide both sides of the equation by 4: 4y / 4 = 16 / 4 This leads to: y = 4 The value of y is 4, which corresponds to the correct answer. This demonstrates that when you plug 4 back into the original equation, it satisfies the equation since: 4(4) + 12 = 16 + 12 = 28. This confirms that the solution is accurate and the value of y is indeed 4.

To find the solution to the equation 4y + 12 = 28, you need to isolate the variable y.

First, start by subtracting 12 from both sides of the equation to eliminate the constant term on the left side:

4y + 12 - 12 = 28 - 12

This simplifies to:

4y = 16

Next, to solve for y, divide both sides of the equation by 4:

4y / 4 = 16 / 4

This leads to:

y = 4

The value of y is 4, which corresponds to the correct answer. This demonstrates that when you plug 4 back into the original equation, it satisfies the equation since:

4(4) + 12 = 16 + 12 = 28.

This confirms that the solution is accurate and the value of y is indeed 4.